A short magnet oscillation in vibration magnetometer with a frequency 10Hz. A downward current of 15A is established in a long vertical wire placed 20cm to the West of the magnet. The new frequency of the short magnet is (the horizontal of the component os earth's magnetic field is `12mu`)

Explain the horizontal and vertical components of earth's magnetic field.

A short bar magnet oscillates in VMM with a frequency of 10Hz. If a downward current of 15A is established in a long thin vertical wire placed 20 cm west of the magnet, its frequency was found to be 5Hz. If a TG containing 500 turns with radius of each turn 4pi cm is used at that place & a current of 10mA is allowed to pass through it. Find the deflection of magnetic needle in the TG

A short magnet oscillates in a vibration magnetometer with a time period of 0.10 s where the horizontal component of earth's magnetic field is 24 mu T . An upward current of 18 A is established in the vertical wire placed 20 cm east of the magnet . Find the new time period.

A short magnet oscillates in a vibration magnetometer with a time period of 0.10 s where the horizontal component of earth's magnetic field is 24 mu T . An upward current of 18 A is established in the vertical wire placed 20 cm east of the magnet . Find the new time period.

A short magnet oscillates in a vibration magnetometer with a time period of 0.10 s where the horizontal component of earth's magnetic field is 24 mu T . An upward current of 18 A is established in the vertical wire placed 20 cm east of the magnet . Find the new time period.

A short bar magnet of magnetic moment 1.2Am^(2) is placed in the magnetic meridian with its south pole pointing the north. If a neutral point is found at a distance of 20cm from the centre of the magnet, the value of the horizontal component of the earth's magnetic field is