[" 12."(15)/(x)+(2)/(y)=17],[(1)/(x)+(1)/(y)=(36)/(5)]

The area bounded by the region between curves y=x^(2)+2,x=0,x=3,y=x+1 is s(A)(15)/(2)(B)(15)/(4)(C)(15)/(3)(D)(17)/(2)

(12x + 17) / (3x + 1)-(2x + 15) / (x + 7) = 3 (1) / (5), x! =-(1) / (3), -7

The reflection of the point (2,-1,3) in the plane 3x-2y-z=9 is (A) (28/7,15/7,17/7) (B) (26/7,-15/7,17/7) (C) (15/7,26/,-17/7) (D) (26/7,17/7,-15/70)

The reflection of the point (2,-1,3) in the plane 3x-2y-z=9 is (A) (28/7,15/7,17/7) (B) (26/7,-15/7,17/7) (C) (15/7,26/,-17/7) (D) (26/7,17/7,-15/70)

The point from which the tangents to the circle x^2 + y^2 - 4x - 6y - 16 = 0, 3x^2 + 3y^2 - 18x + 9y + 6 = 0 and x^2 + y^2 - 8x - 3y + 24 = 0 are equal in length is : (A) (2/3, 4/17) (B) (17/16, 4/15) (C) (17/16, 4/15) (D) (5/4, 2/3)

Solve: (12x+17)/(3x+1)-(2x+15)/(x+7) = 3 1/5[x!= -1/3,-7]

(17-15x-2x ^ (2)) / (x + 3) <0

(sqrt(2x^(2)+15x-17))/(10-x)>=0