Show that the volume of a segment of height h of a sphere of radius R is
`V=(1)/(3)pi h^(2)(3R-h)`

Using the method of integration, show that the volume of a right circular cone of base radius r and height h is V=1/3pir^2h .

What is volume of the frustum of a cone with height h and radii r_(1),r_(2) ?

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius R is 2(R)/(sqrt(3)) .Also find maximum volume.

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius R is (2R)/(sqrt(3)) Also find the maximum volume.

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius R is (2R)/(sqrt(3))

Show that the altitude of the right circular cone of maximum volume that can be inscribed in a sphere of radius R is (4R)/(3) .

Frame the formula for the volume (v) of a cylinder given by the product of pi , square of radius (r) and height (h).

If h is the height, I the slant height and r_(1), r_(2) radii of the circular bases of the frustum of a cone, then slant height of the frustum = sqrt(( r_(1) - r_(2))^(2) + h^(2)) . Height of the cone of which the frustum is a part = (h r_(1) /( r_(1) - r_(2) ).We have a bucket in the form of frustum of a cone in which h = 8 cm, r_(1) = 9 cm and r_(2) = 3 cm. Find its volume.