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A particle starts moving rectilinearly a...

A particle starts moving rectilinearly at time `t = 0` such that its velocity(v) changes with time (t) as per equation –
`v = (t2 – 2t) m//s` for `0 lt t lt 2 s`
`= (–t^(2) + 6t – 8) m//s` for `2 le te 4 s`
(a) Find the interval of time between `t = 0` and `t = 4 s` when particle is retarding.
(b) Find the maximum speed of the particle in the interval `0 le t le 4 s`.

Text Solution

Verified by Experts

The correct Answer is:
(a) `1 lt t lt 2s` and `3 lt t lt 4s` (b) `1m//s`
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Knowledge Check

  • A particle starts moving rectillineraly at time t = 0 , such that its velocity 'v' changes with time 't' according to the equation v = t^(2) -t where t is in seconds and v is in m//s . The time interval for which the particle retards is

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