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A bead moves along a straight horizontal...

A bead moves along a straight horizontal wire of length L, starting from the left end with velocity v0. Its retardation is proportional to the distance that remains to the right end of the wire. Find the initial retardation (at left end of the wire) if the bead reaches the right end of the wire with a velocity `(v_(0))/(2)`.

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The correct Answer is:
`(3v_(0)^(2))/(4L)`
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