Two bodies 1 and 2 of different shapes are released on the surface of a deep pond. The mass of the two bodies are `m_(1) = 1 kg` and `m_(2) = 1.2 kg` respectively. While moving through water, the bodies experience resistive force given as `R = bv`, where v is speed of the body and b is a positive constant dependent on shape of the body. For bodies 1 and 2 value of b is `2.5 kg//s` and `3.0 kg//s` respectively. Neglect all other forces apart from gravity and the resistive force, while answering following questions : [Hint : acceleration `= "force"//"mass"]`
(i) With what speed `v_(10)` and `v_(20)` will the two bodies hit the bed of the pond. [Take `g = 10 m//s^(2)]`
(ii) Which body will acquire speed equal to half the terminal speed in less time.

Answer

(i) `v_(10) = v_(20) = 4m//s` (ii) Both will take same time