A meter stick AB is lying on a horizontal table. Its end A is pulled up so as to move it with a constant velocity `V_(A) = 4ms^(–1)` along a vertical line. End B slides along the floor.

(a) After how much time `(t_(0))` speed `(V_(B))` of end B becomes equal to the speed `(V_(A))` of end A ?
(b) Find distance travelled by the end B in time `t_(0)`.

Answer

(a) `t_(0) = (1)/(4sqrt(2)) s` (b) `(1-(1)/(sqrt(2)))m`