A water sprinkler is positioned at O on horizontal ground. It issues water drops in every possible direction with fixed speed u. This way the sprinkler is able to completely wet a circular area of the ground (see fig). A horizontal wind starts blowing at a speed of `(u)/(2sqrt(2))`.Mark the area on the ground that the sprinkler will now be able to wet.

Answer

A circle of same size shifted from the original circle by `DeltaX = (u^(2))/(2g)` in the direction of wind.