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In the arrangement shown in the figure, ...

In the arrangement shown in the figure, the block C begins to move down at a constant speed of `7.5 cm//s` at time `t = 0`. At the same instant block A is made to start moving down at constant acceleration. It starts at M and its speed is `30 cm//s` when it reaches `N (MN = 20 cm)`. Assuming that B started from rest, find its position, velocity and acceleration when block A reaches N.

Text Solution

Verified by Experts

The correct Answer is:
Position; 40 cm up from starting position
`V_(B) = 45 cm//s (uarr)`
`a_(B) = 22/5 cm//s^(2) (uarr)`
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