A wet umbrella is held upright (see figure). The man holding it is rotating it about its vertical shaft at an angular speed of `omega = 5` rad `s^(–1)`. The rim of the umbrella has a radius of `r = 0.5` m and it is at a height of `H = 1.8` m from the floor. The man holding the umbrella gradually increases the angular speed to make it `2 omega`. Calculate the area of the floor that will get wet due to water drops spun off the rim and hitting the floor. `[g = 10 m//s^(2)]`.

Answer

`21.2 m^(2)`