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A disc of mass m lies flat on a smooth h...

A disc of mass m lies flat on a smooth horizontal table. A light string runs halfway around it as shown in figure. One end of the string is attached to a particle of mass m and the other end is being pulled with a force F. There is no friction between the disc and the string. Find acceleration of the end of the string to which force is being applied.

Text Solution

Verified by Experts

The correct Answer is:
`(5F)/(m)`
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Knowledge Check

  • A block of mass M is pulled on a smooth horizontal table by a string making an angle theta with the horizontal as shown in figure. If the acceleration of the block is a find the force applied by the string and by the table N on the block.

    A
    `T=(Ma)/(tantheta)` , `N=(Mg-Ma tan theta)`
    B
    `T=(Mg)/(costheta)` , `N=(Mg-Ma tan theta)`
    C
    `T=(Ma)/(costheta)` , `N=(Mg-Ma cos theta)`
    D
    `T=(Ma)/(costheta)` , `N=(Mg-Ma tan theta)`

  • One end of string of length /mass 'm' and the other end is smooth horizontal table. If the speed 'v', the net force on th center) will be: (T represents the tension in the on the particles tension in the string)

    A
    `T + (mv^(2))/I`
    B
    `T-(mv^(2))/l`
    C
    Zero
    D
    1

  • A uniform rod of mass m length l is attached to smooth hinge at end A and to a string at end B as shown in figure. It is at rest. The angular acceleration of the rod just after the string is cut is :

    A
    `(3g)/(2l)`
    B
    `(3g)/(4l)`
    C
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    D
    `(5g)/(2l)`

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