In the system shown in fig, mass of the block is `m_(1) = 4` kg and that of the hanging particle is `m_(2) = 1` kg. The incline is fixed and surface is smooth. Block is initially held at the top of the incline and the particle hangs a distance d = 2.0 m below it. [Assume that the block and the particle are on same vertical line in this position]. System is released from this position. After what time will the distance between the block and the particle be minimum ? Find this minimum distance. [ `g = 10 m//s^(2)`.]

Answer

1.0 s , 1.0 m