In the arrangement shown in the fig. a monkey of mass M keeps itself as well as block A at rest by firmly holding the rope. Rope is massless and the pulley is ideal. Height of the monkey and block A from the floor is h and 2h respectively [h = 2.5 m]
(a) The monkey loosens its grip on the rope and slides down to the floor. At what height from the ground is block A at the instant the money hits the ground?
(b) Another block of mass equal to that of A is stuck to the block A and the system is released. The monkey decides to keep itself at height h above the ground and it allows the rope to slide through its hand. With what speed will the block strike the ground?
(c) In the situation described in (b), the monkey decides to prevent the block from striking the floor. The monkey remains at height h till the block crosses it. At the instant the block is crossing the monkey it begins climbing up the rope. Find the minimum acceleration of the monkey relative to the rope, so that the block is not able to hit the floor. Do you think that a monkey can climb with such an acceleration? (`g = 10ms^(-2)`)

Answer

(a) The block is at height h = 2.5
(b) `V = 5sqrt(2) m//s`
`25 m//s^(2) uparrow`