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In the system shown in the fig. there is...

In the system shown in the fig. there is no friction and string is light. Mass of movable pulley `P_(2) "is" M_(2)`. If pulley `P_(1)` is massless, what should be value of applied force F to keep the system in equilibrium?

Text Solution

Verified by Experts

The correct Answer is:
With pulley `P_(1)` having zero mass , equilibrium is not possible
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Knowledge Check

  • In the system shown in fig the pulley is frictionless and the string massless if m_(1)=m_(2) thrust on the pulley will be:

    A
    `"less than" (m_(1)+m_(2))g`
    B
    `"greater than" (m_(1)+m_(2))g`
    C
    `"equal to "(m_(1)+m_(2))g`
    D
    none of the above

  • In the system shown in the figure, which the following is correct? (Pulleys and strings are of negligible mass)

    A
    The system can never be in equilibrium
    B
    The system remains in equilibrium at `theta=45^(@)`
    C
    If the masses of A and C are changed then the equilibrium angle (if any) changes
    D
    If all the masses are doubled, the equilibrium angle (if any) remains same.

  • The system shown in th fig is released from rest. (Neglecting friction and mass of the pulley, string and spring). The spring can be elongated:

    A
    if `M gt m`
    B
    if `M gt 2m`
    C
    if `M gt m/2`
    D
    for any value of M (M should be greater than zero)

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