A wedge of mass m is placed on a horizontal smooth table. A block of mass m is placed at the mid point of the smooth inclined surface having length L along its line of greatest slope. Inclination of the inclined surface is `theta= 45^(@)`. The block is released and simultaneously a constant horizontal force F is applied on the wedge as shown.
(a) What is value of F if the block does not slide on the wedge?
(b) In how much time the block will come out of the incline surface if applied force is 1.5 times that found in part (a)

Answer

(a) 2 mg
(b) `t = sqrt((3L)/(sqrt2)g))`