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In order to lift a heavy block A, an eng...

In order to lift a heavy block A, an engineer has designed a wedge system as shown. Wedge C is fixed. A horizontal force F is applied to B to lift block A. Wedge B itself has negligible mass and mass of A is M. The coefficient of friction at all surfaces is `mu`. Find the value of applied force F at which the block A just begins to rise.

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The correct Answer is:
`F = (Mg)/(1 - mu^(2))[mu + (mu"cos"theta + "sin"theta)/("cos"theta - mu"sin"theta)]`
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