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A uniform rope of length (piR)/(2) has ...

A uniform rope of length `(piR)/(2)` has been placed on fixed cylinder of radius R as shown in the fig. One end of the rope is at the top of the cylinder. The coefficient of friction between the rope and the cylinder is just enough to prevent the rope from sliding. Mass of the rope is M.
(a) At what position, the tension in the rope is maximum?
(b) Calculate the value of maximum tension in the rope.

Text Solution

Verified by Experts

The correct Answer is:
(a) `theta = 45^(@)` from vertical diameter .
(b) `T_("max") = 2 ((sqrt2-1)/(pi))Mg`
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