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A semicircular ring of radius R is fixed...

A semicircular ring of radius R is fixed on a smooth horizontal table. A small block is projected with speed u so as to enter the ring at end A. Initial velocity of the block is along tangent to the ring at A and it moves on the table remaining in contact with the inner wall of the ring. The coefficient of friction between the block and the ring is `mu`.
(a) Find the time after which the block will exit the ring at B.
(b) With what speed will the block leave the ring at B.

Text Solution

Verified by Experts

The correct Answer is:
(a) `t = (R)/(muu) [e^(pimu) - 1]`
(b) ` V = (u)/(e^(pimu))`
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