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A particle of mass m = 1 kg is moving in...

A particle of mass `m = 1 kg` is moving in space in X direction with a velocity of `10 ms^(-1)`. A 4 N force acting in Y direction is applied on it for a time interval of `5.0 s`. Later a 5 N force was applied on it in Z direction for `4.0 s`
(a) Calculate the total work done by both the forces.
(b) Which force performed greater work ?

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The correct Answer is:
(a) 400 J
(b) Both performed equal work.
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