Two blocks of mass `m_(1) and m_(2)` are moving along a smooth horizontal floor. A non-ideal spring is attached at the back of mass `m_(2)`. Initial velocities of the blocks are `u_(1) and u_(2)` as shown, with `u_(1) gt u_(2)`. After collision the two blocks were found to be moving with velocities `V_(1) and V_(2)` respectively. Find the ratio of impulse (on each block) during the deformation phase of the spring and that during its restoration phase. [By non ideal spring we mean that it does not completely regain its original shape after deformation. You can neglect the mass of the spring.]

Answer

`(u_(1)-u_(2))/(V_(2)-V_(1))`