Two particles `P and Q` have mass `1 kg and 2 kg` respectively. They are projected along a vertical line with velocity `u_(p) = 20` m/s and `u_(Q) = 5` m/s when separation between them was 60 m. P was projected vertically up while Q was projected vertically down. Calculate the maximum height attained by the centre of mass of the system of two particles, measured from the initial position of P. Assume that the particles do not collide and that the ground is far below their point of projection `[g = 10 m//s^(2)] `

Answer

40.56 m