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Two blocks A and B, each of mass m, are connected by a spring of force constant K. Initially, the spring is in its natural length. A horizontal constant force F starts acting on block A at time `t=0` and at time t , the extension in the spring is seen to be `l`. What is the displacement of the block A in time `t` ?

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The correct Answer is:
`(Ft^(2))/(4m)+(l)/(2)`
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