Angular speed of rotation of the earth is `omega_(0).` A train is running along the equator at a speed v from west to east. A very sensitive balance inside the train shows the weight of n object as `W_(1).` During the return journey when the train is running atsame speed from east to west the balance shows the weight of the object to be `W_(2).` Weight of the object when the train is at rest was shown to be `W_(0)` by the balance. Calculate `W_(2) – W_(1).`

Answer

`(4W_(0)omega_(0)v)/(g)`