A celestial body, not bound to sun, will only pass by the sun once. Calculate the minimum speed of such a body when it is at a distance of `1.5xx10^(11)m` from the sun (this is verage distancebetween the sun & the earth and is known as astronomical unit- A.U.) The mass of the sun is ` M underline~2xx10^(30)kg.` `G=6.67xx10^(-11)(N-m^(2))/(kg^(2))` Show that this speed is`sqrt(2)` times greater than speed of earth around the sun, assuming circular trajectory

Answer

`4.2xx10^(-4) m//s`