A horizontal tube having cross sectional area `A_(1)=10cm^(2)` has a venturi connected to it having cross sectional area `A_(2)=4 cm^(2)`. A moanometer, having mercury as its liquid is connected to be has uniform cross section and it has a horizontal part of lenght L=10cm. When there is no flow in the tube the height of mercuty column in both vertical arms is H=12cm. calculate the minimum flow rate (in `m^(3)//s`) of air through the tube if it is required that the entire amount of mercury move to one vertical arm of the manometer. Gives, density of `Hg=13.6xx10^(3)kgm^(3)`, density of air=1.2 kg `m^(-3)`.

Answer

`12.1m^(3)s^(-1)`