A soap bubble has radius R and thickness of its wall is a. Calculate the apparent weight `(= true weight - Buoyancy)` of the bubble if surface tension of soap solution and its density are T and d respectively. The atmospheric pressure is `P_(0)` and density of atmospheric air is `rho_(0)`. By assuming `a = 10^(–6) m, R = 10 cm, P_(0) = 10^(5) Nm^(–2), rho_(0) = 1.2 kg m^(–3), d = 10^(3) kg m^(–3), T = 0.04 Nm^(–1)`, show that the weight of the bubble is mainly because of water in the skin. What is weight of the bubble?

Answer

`(16pi)/3 (R^(2)rho_(o))/P_(o) g+4piR^(2)` a.d.g