Home
Class 11
PHYSICS
An ideal gas expands following a relatio...

An ideal gas expands following a relation `(P^(2))/(rho)`= constant, where P = pressure and `rho` = density of the gas. The gas is initially at temperature T and density `rho` and finally its density becomes `(rho)/(3)`.
(a) Find the final temperature of the gas. (b) Draw the P – T graph for the process.

Text Solution

Verified by Experts

The correct Answer is:
(a) `sqrt(3) T`
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    ARIHANT|Exercise Level 2|18 Videos

  • KINETIC THEORY OF GASES

    ARIHANT|Exercise Level 3|4 Videos

  • KINEMATICS

    ARIHANT|Exercise Level 3|33 Videos

  • MOMENTUM AND CENTRE OF MASS

    ARIHANT|Exercise Momentum And Center of Mass|117 Videos

Similar Questions

Explore conceptually related problems

During an experiment, an ideal gas is found to obey a condition (p^2)/(rho) = "constant" . ( rho = density of the gas). The gas is initially at temperature (T), pressure (p) and density rho . The gas expands such that density changes to rho//2 .

It P is the pressure and rho is the density of a gas, then P and rho are realted as :

The ednsity (rho) of an ideal gas varies with temperature T as shown in figure. Then

Figure shows graphs of pressure vs density for an ideal gas at two temperatures T_(t) and T_(2)

The density of the given gas at constant pressure and temperature is rho and its rate of diffusion isr. If density of the gas becone rho//3 then rate of diffusion becomes

A gas is found to be obeyed the law p^2V = constant . The initial temperature and volume are T_0 and V_0 . If the gas expands to a volume 3 V_0 , then the final temperature becomes.

Figure shows graphs of pressure versus density for an ideal gas at two temperatures T_1 and T_2 Then