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A particle of mass m is thrown along a h...

A particle of mass m is thrown along a horizontal surface with speed u and comes to rest after travelling a distance `x_(0)`. A uniform magnetic field `B_(0)` is switched on in vertically downward direction and the particle is projected as before after putting a charge q on it. This time it travelled through a distance `X_(1)` before stopping. Now the experiment is repeated with a uniform electric field E0 in addition to the magnetic field, electric field being parallel to the magnetic field. Particle having mass m and charge q is projected as earlier and found to travel a distance `X_(2)` before stopping. Find `X_(1)` and `x_(2)`

Text Solution

Verified by Experts

The correct Answer is:
`X_(1)=X_(0);X_(2)=(mgX_(0))/(mg+qE_(0))`
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