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If y= 2x-3 is a tangent to the parabola ...

If y= 2x-3 is a tangent to the parabola `y^2 = 4a(x-1/3)` then 'a' is equal to:

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Equation of a tangent to parabola `y^2 = 4ax` is given by,
`y = mx+a/m`
Now, equation of the given parabola is,
`y^2 = 4a(x-1/3)`
So, equation of tangent will be,
`y = m(x-1/3)+a/m`
`=>y = mx- m/3+a/m->(1)`
Given equation of tangent is,
...
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