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If the dimensions of a physical quantity...

If the dimensions of a physical quantity are given by `M^(x) L^(y) T^(z)`, then physical quantity may be

A

acceleration due to gravity, if `x=0, y=1, z=-2`

B

atmospheric pressure, if `x=1, y=1, z=-2`

C

linear momentum, if `x=1, y=1, z=-1`

D

potential energy, if `x=1, y=2, z=-2`

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
For (A) : `["Acceleration"]=[LT^(-2)]`
For (B) : `["Energy"]=[ML^(2)T^(-2)]`
for (C) : `["Momentum"]=[MLT^(-1)]`
For (D) : `["Energy"]=[ML^(2)T^(-2)]`
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