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Force on a particle in one-dimensional m...

Force on a particle in one-dimensional motion is given by `F=Av+Bt+(Cx)/(At+D)`, where F= force, v= speed, t= time, x= position and A, B, C and D are constants. Dimension of C will be-

A

`M^(2)L^(-2)T^(0)`

B

`ML^(-1)T^(0)`

C

`M^(2)L^(0)T^(-2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`dim(A)=dim(F/v) rArr dim(C)=dim[(F(At+D))/x]=dim[F/x((Ft)/v)]=dim[(F^(2)t)/(xv)]=dim[F^(2)/v^(2)]=[M^(2)T^(-2)]`
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