Five point charges, each of value +q are placed on five vertices of a regular hexagon of side Lm. What is the magnitude of the force on a point charge of value -q coulomb placed at the centre of the hexagon?

Explanation

To find the magnitude of the force on a point charge of value -q placed at the center of a regular hexagon with five point charges of value +q at its vertices, we can follow these steps:

### Step 1: Understand the Configuration
We have a regular hexagon with five positive charges (+q) placed at five of its vertices. The sixth vertex is empty. A negative charge (-q) is placed at the center of the hexagon.

### Step 2: Calculate the Distance from the Center to the Vertices
The distance from the center of the hexagon to any vertex is equal to the radius of the circumcircle of the hexagon. For a regular hexagon with side length L, this distance (r) can be calculated as:
\[ r = \frac{L}{\sqrt{3}} \]
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