Home
Class 11
PHYSICS
A point charge of 0.009 mu C is placed a...

A point charge of `0.009 mu C` is placed at origin.
Calculate intensity of electric field due to this point charge at point `(sqrt(2), sqrt(7), 0)`.

Text Solution

Verified by Experts

`vec(E)=(qvec(r))/(4pi in_(0)r^(3))`, where `vec(r)=xhat(i)+yhat(j)=sqrt(2)hat(i)+sqrt(7)hat(j), vec(E)=(9xx10^(5)xx9xx10^(-9)(sqrt(2)hat(i)+sqrt(7)hat(j)))/((3)^(3))=(3sqrt(2)hat(i)+3sqrt(7)hat(j))NC^(-1)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN|Exercise Part -II Example Some worked out Examples|1 Videos

  • MISCELLANEOUS

    ALLEN|Exercise Exercise-01|87 Videos

  • MISCELLANEOUS

    ALLEN|Exercise SUBJECTIVE QUESTION|9 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-IV|8 Videos

Similar Questions

Explore conceptually related problems

Electric field due to point charge

A point charge of 0.01 mu C is placed at the origin. Calculate the electric field at another point charge of 0.05 mu C placed at (0 m, 5 m).

Knowledge Check

  • a point change of 0.009 muC is placed at origin. the intensity of electric field due to the charge at a point (sqrt2, sqrt7, 0) is

    A
    `(3sqrt2 hati + 3sqrt7 hatj) NC^-1`
    B
    `(2sqrt3 hati + 3sqrt7 hatj) NC^-1`
    C
    `(3sqrt2 hati + 7sqrt3 hatj) NC^-1`
    D
    `(sqrt2 hati + 7sqrt3 hatj) NC^-1`

  • A point charge of 100mu C is placed at 3 hat j+4 hat j m . Find the electric field intensity due to this chargaes at a point located at 9 hat j+12 hat j m .

    A
    `8000Vm^(-1)`
    B
    `9000Vm^(-1)`
    C
    `2250Vm^(-1)`
    D
    `4500Vm^(-1)`

    • Similar Questions

    Explore conceptually related problems

    Electric Field Due To A Point Charge Vector Notation

    A point charge q is placed at the origin . How does the electric field due to the charge very with distance r from the origin ?

    Electric Field Due To An Isolated Point Charge

    An electric dipole is placed in an electric field generated by a point charge then

    An electric dipole is placed in an electric field generated by a point charge then

    Derive an expression for electric field intensity at a point due to point charge.

    Home
    Profile