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The two conducting spherical shells are ...

The two conducting spherical shells are joined by a conducting wire and cut after some time when charge stops flowing. Find out the charge on each sphere after that.

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After cutting the wire, the potential of both the shells is equal
Thus, potential of inner shell `V_("in")=(Kx)/(R)+(K(-2Q-x))/(2R)=(K(x-2Q))/(2R)`
and potential of outer shell `V_("out")=(Kx)/(2R)+(K(-2Q-x))/(2R)=(-KQ)/(R)`
As `V_("out")=V_("in")rArr (-KR)/(R)=(K(x-2Q))/(2R)rArr -2Q=x-2Q rArr x=0`
So charge on inner spherical shell `=0` and outer spherical shell `=-2 Q`
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