A metallic rod of length I rotates at angular velocity `omega` about an axis passing through one end and perpendicular to the rod. If mass of electron is m and its charge is -e then the magnitude of potential difference between its two ends is

Options

A. `(m omega^(2)l^(2))/((2e))`
B. `(m omega^(2)l^(2))/(e)`
C. `(m omega^(2)l)/(e)`
D. None of these

Answer

A

Explanation

When rod the centripetal acceleration of electron comes electric from electric field `E=(mromega^(2))/(e)`
Thus, `DeltaV=-int vec(E).dr=-underset(0)overset(l)(int)(mromega^(2))/(e)dr=(momega^(2)l^(2))/(2e)`