The arrangement shown consists of three elements.
(i) A thin rod of charge `-3.0 mu C` that froms a full circule of radius `6.0 cm`.
(ii) A second thin rod of charge `2.0 mu C` that forms a circular are of radius `4.0 cm` and concentric with the full circle, subtending an angle of `90^(@)` at the centre of the full circle.
(iii) an electric dipole with a dipole moment that is perpendicular to a radial line and has magnitude `1.28xx10^(-21) C-m`.
Find the net electric potential in volts at the centre.

Answer

0

Explanation

Potential due to dipole at the centre of the circle is zero.
Potentials due to charge on circle `=V_(1)=(K.(-3xx10^(-6)))/(6xx10^(-2))`
Potential due to are `V_(2)=(K.(2xx10^(-6)))/(4xx10^(-2))` Net potential `=V_(1)+V_(2)=0`