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There are two force vectors, one of 5 N ...

There are two force vectors, one of `5 N` and other of `12 N` at what angle the two vectors be added to get resultant vector of `17 N, 7 N` and `13 N` respectively.

A

`0^(@), 180^(@)` and `90^(@)`

B

`0^(@), 90^(@)` and `180^(@)`

C

`0^(@), 90^(@)` and `90^(@)`

D

`180^(@), 0^(@)` and `90^(@)`

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The correct Answer is:
To solve the problem of finding the angle between two force vectors of magnitudes \( F_1 = 5 \, \text{N} \) and \( F_2 = 12 \, \text{N} \) that results in different resultant vectors of \( R = 17 \, \text{N} \), \( R = 7 \, \text{N} \), and \( R = 13 \, \text{N} \), we can use the formula for the resultant of two vectors: \[ R^2 = F_1^2 + F_2^2 + 2 F_1 F_2 \cos \theta \] ### Step-by-Step Solution: 1. **Identify the Given Values**: - \( F_1 = 5 \, \text{N} \) - \( F_2 = 12 \, \text{N} \) 2. **Calculate \( F_1^2 \) and \( F_2^2 \)**: - \( F_1^2 = 5^2 = 25 \) - \( F_2^2 = 12^2 = 144 \) 3. **Set Up the Resultant Equation**: - The equation becomes: \[ R^2 = 25 + 144 + 2 \cdot 5 \cdot 12 \cos \theta \] - Simplifying gives: \[ R^2 = 169 + 120 \cos \theta \] 4. **Case 1: Resultant \( R = 17 \, \text{N} \)**: - Substitute \( R = 17 \): \[ 17^2 = 169 + 120 \cos \theta \] - This simplifies to: \[ 289 = 169 + 120 \cos \theta \] - Rearranging gives: \[ 120 \cos \theta = 289 - 169 = 120 \] - Thus: \[ \cos \theta = \frac{120}{120} = 1 \] - Therefore, \( \theta = \cos^{-1}(1) = 0^\circ \). 5. **Case 2: Resultant \( R = 7 \, \text{N} \)**: - Substitute \( R = 7 \): \[ 7^2 = 169 + 120 \cos \theta \] - This simplifies to: \[ 49 = 169 + 120 \cos \theta \] - Rearranging gives: \[ 120 \cos \theta = 49 - 169 = -120 \] - Thus: \[ \cos \theta = \frac{-120}{120} = -1 \] - Therefore, \( \theta = \cos^{-1}(-1) = 180^\circ \). 6. **Case 3: Resultant \( R = 13 \, \text{N} \)**: - Substitute \( R = 13 \): \[ 13^2 = 169 + 120 \cos \theta \] - This simplifies to: \[ 169 = 169 + 120 \cos \theta \] - Rearranging gives: \[ 120 \cos \theta = 169 - 169 = 0 \] - Thus: \[ \cos \theta = 0 \] - Therefore, \( \theta = \cos^{-1}(0) = 90^\circ \). ### Summary of Angles: - For \( R = 17 \, \text{N} \), \( \theta = 0^\circ \) - For \( R = 7 \, \text{N} \), \( \theta = 180^\circ \) - For \( R = 13 \, \text{N} \), \( \theta = 90^\circ \) ### Final Answer: The angles between the vectors for the respective resultant forces are: - \( 0^\circ \), \( 180^\circ \), and \( 90^\circ \).

To solve the problem of finding the angle between two force vectors of magnitudes \( F_1 = 5 \, \text{N} \) and \( F_2 = 12 \, \text{N} \) that results in different resultant vectors of \( R = 17 \, \text{N} \), \( R = 7 \, \text{N} \), and \( R = 13 \, \text{N} \), we can use the formula for the resultant of two vectors: \[ R^2 = F_1^2 + F_2^2 + 2 F_1 F_2 \cos \theta \] ### Step-by-Step Solution: ...
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