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The van der wasl's equation of a gas is ...

The van der wasl's equation of a gas is `(P+(aT^(2))/V) V^(c)=(RT+b)`. Where a, b, c and R are constant. If the isotherm is represented by `P=AV^(m)-BV^(n)`, where A and B depends on temperature:

A

`m=-c, n=-1`

B

`m=+c, n=-1`

C

`m=-c, n=+1`

D

`m=c, n=-1`

Text Solution

Verified by Experts

The correct Answer is:
A
`P+(aT^(2))/V=(RT+b)V^(-c)`
`rArr P =(RT+b)V^(-C)-aT^(2)V^(-1)=AV^(m)-BV^(n)`
`rArr m=-c` and `n=-1`
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