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Three forces P,Q and R are acting at a p...

Three forces P,Q and R are acting at a point in the plane. The angle between P & Q and Q & R are `150^(@) & 120^(@)` respectively, then for equilibrium, forces P,Q & R are in the ratio

A

`1:2:3`

B

`1:2:sqrt(3)`

C

`3:2:1`

D

`sqrt(3):2:1`

Text Solution

Verified by Experts

The correct Answer is:
D


`P/(sin 120^(@))=Q/(sin 90^(@))=R/(sin 150^(@))`
`rArr P/(sqrt(3)//2)=Q/1=R/(1//2)`
`rArr (2P)/sqrt(3)=Q/1=(2R)/1=k` (constant)
`rArr P : Q : R=(sqrt(3)k)/2: k: k/2=sqrt(3):2:1`
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