In the formula `P=(nRT)/(V-b)e^(-a/(RTV))`. Find the dimensions of a and b where P= pressure, n= number of moles. T= temperature, V= volume and R= universal gas constant.

Answer

`[a]=ML^(5)T^(-2) mol^(-1), [b]=L^(3)`

Explanation

`[b]=[v]=[L^(3)]` dimensions of `a/(RTV)=[M^(o)L^(o)T^(o)]`
`rArr [a]=` dimensions of RTV
`=[(M^(1)L^(2)T^(-2))/(k xxmol)]xx[k]xx[L^(3)]=[M^(1)L^(5)T^(-2) mol^(-1)]`