Home
Class 11
PHYSICS
A particle moves in such a manner that x...

A particle moves in such a manner that `x=At, y=Bt^(3)-2t, z=ct^(2)-4t`, where x, y and z are measured in meters and t is measured in seconds, and A, B and C are unknown constants. Give that the velocity of the particle at `t=2s` is `vec(v)=((dvec(r))/(dt))=3hat(i)+22hat(j) m//s`, determine the velocity of the particle at `t=4s`.

Text Solution

Verified by Experts

The correct Answer is:
`(3hat(i)+94hat(j)+4hat(k)) m//s`

`vec(v)=Ahat(i)+(3Bt^(2)-2)hat(j)+(2ct-4)hat(k)`
At `t=2, Ahat(i)+(12B-2)hat(j)+(4c-4)hat(k)=3hat(i)+22hat(j)`
Thus, `A=3, B=2, C=1`
`:. Vec(v)=3hat(i)+(6t^(2)-2)hat(j)+(2t-4)hat(k)`
At `t=4, vec(v)=3hat(i)+(96-2)hat(j)+(8-4)hat(k)=3hat(i)+94hat(j)+4hat(k)`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN|Exercise EXERCISE-5(A)|15 Videos
  • MISCELLANEOUS

    ALLEN|Exercise Exersice -05(B)|20 Videos
  • MISCELLANEOUS

    ALLEN|Exercise Exercise-04 [A]|28 Videos
  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos
  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-IV|8 Videos

Similar Questions

Explore conceptually related problems

A particle moves along positive branch of the curve, y = x/2, where x = t^3/3 , x and y are measured in meters and t in seconds, then

The position of a particle is given by vec(r) = 3that(i) - 4t^(2)hat(j) + 5hat(k). Then the magnitude of the velocity of the particle at t = 2 s is

A particle moves on the curve y = x^(2)/4 where x=t/2. x and y are meausured in metre and t in second. At t=4s the velocity of particel is

A particle is moving such that s=t^(3)-6t^(2)+18t+9 , where s is in meters and t is in meters and t is in seconds. Find the minimum velocity attained by the particle.

A particle moves such that x = 2t^(3) + t+ 8, y=t^(2) + t+ 3 and z=3 sin pit where x, y, z are in meter and t in seconds. Calculate the acceleration of the particle at t = 3 second.

A particle is given an initial velocity of vecu=(3 hati+4 hatj) m//s . Acceleration of the particle is veca=(3t^(2) +2 thatj) m//s^(2) . Find the velocity of particle at t=2s.

A particle moves along the positive branch of the curve y = (x^(2))/(2) where x = (t^(2))/(2),x and y are measured in metres and t in second. At t = 2s , the velocity of the particle is

If displacement of particle is s=(t^(3))/(3)-(t^(2))/(2)-(t)/(2)+6 , then velocity of the particle at t=4 sec. is

A particle moves along the positive branch of the curve with x governed by where x and y are measured in meters and t in seconds. At t = 2s, the velocity of the particle is

A particle moves along the positive branch of the curve y =2x2where x =2t2,where x and y are measured in metre and t in second. At t = 2 sec, the velocityof the particle is -