Home
Class 11
PHYSICS
Let [in(0)] denote the dimensional formu...

Let `[in_(0)]` denote the dimensional formula of the permittivity of vacuum. If M= mass, L=length, T=Time and A= electric current, then:

A

`[in_(0]=[M^(-1)L^(-3)T^(2)A]`

B

`[in_(0)]=[M^(-1)L^(-3)T^(4)A^(2)]`

C

`[in_(0)]=[M^(-1)L^(2)T^(-1)A^(-2)]`

D

`[in_(0)]=[M^(-1)L^(2)T^(-1)A]`

Text Solution

Verified by Experts

The correct Answer is:
B
`F=(1)/(4pi in_(0))(q_(1)q_(2))/r^(2)rArr [MLT^(-2)]=[1/in_(0)] (A^(2)T^(2))/L^(2)`
`rArr [epsilon_(0)]=[M^(-1)L^(-3)T^(4)A^(2)]`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN|Exercise Exersice -05(B)|20 Videos

  • MISCELLANEOUS

    ALLEN|Exercise Exercise-02|77 Videos

  • MISCELLANEOUS

    ALLEN|Exercise Exersice-4[B]|14 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-IV|8 Videos

Similar Questions

Explore conceptually related problems

Let [in_(0)] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = elctric current , then :

Let [epsi_(0)] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T= time and A= electric current, then

Let epsi_0 denote the dimensional formula of the permittivity of vacuum. If M= mass , L=length , T=time and A=electric current , then dimension of permittivity is given as [M^(p)L^(q)T^(r)A^(s)] . Find the value of (p-q+r)/(s)

Let [varepsilon_0] denote the dimensional formula of the permittivity of vacuum. If M =mass , L=length, T=time and I= electric current Then

What is the dimensional formula of electric permittivity of free space?

Let [epsilon_(0)] denote the dimensional formula of the permittivity of the vacuum and [mu_(0)] that of the permeability of the vacuum. If M= mass, L=length, T= time and I= electric current

Let [epsi_(0)] denote the dimensional formula of the permittivity of the vacuum and [mu_(0)] that of the permeability of the vacuum. If M = mass, L = length, T = time and I = electric current :

Let [epsilon_(0)] denote the dimensional formula of the permittivity of the vacuum, and [mu_(0)] that of the permeability of the vacuum. If M = mass ,L = length, T = time and I = electric current ,

Let [in_(0)] denote the dimensional formula of the permittivity of the vacuum and [mu_(0)] that of the permability of the vacuum.If M="mass",L="length",T-"time" and I="electric current"