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The currect voltage relation of diode is...

The currect voltage relation of diode is given by `1=(e^(1000 V//T)-1) mA`, where the applied voltage V is in volt and the temperature T is in degree Kelvin. If a student makes an error measuring `+-0.01 V` while measuring the current of `5 mA` at `300 K`, what will be error in the value of current in mA?

A

`0.5 mA`

B

`0.05 mA`

C

`0.2 mA`

D

`0.02 mA`

Text Solution

Verified by Experts

The correct Answer is:
C
Given current `I=(e^(1000 V//T)-1) mA`
`rArr 1+1=e^(1000V//T)`
`dI=1000/T[e^((1000V)/T)]dV`
`dI=1000/T[I+1]dV`
`1000/300 [6]xx(0.01)`
`dI=0.2 mA`
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