The dimensions of `1/2 epsilon_(0)E^(2) (epsilon_(0)=` permittivity of free space, `E=` electric field) is

Options

A. `[MLT^(-1)]`
B. `[ML^(2)T^(-2)]`
C. `[ML^(-1)T^(-2)]`
D. `[ML^(2)T^(-1)]`

Answer

C

Explanation

`1/2 in_(0) E^(2)-[M^(-1)L^(-3)T^(4)I^(2)][M^(2)L^(2)T^(-6)I^(-2)]=[M^(1)L^(-1)T^(-2)]`