The SI unit of the inductance, the henry can by written as-

Options

A. Weber`//`ampere
B. Volt-second`//`ampere
C. Joule`//("ampee")^(2)`
D. ohm-second

Answer

A, B, C, D

Explanation

`e=L(di)/(dt) rArr ("volt-sec")/("Ampere")=L("Henery")`
`L/R=` Time constant , `[L]=ohm-sec`
`phi=LIrArr ("weber")/("Ampere")=L("Henery")`
`E=1/2 rArr LI^(2)=("Joule")/(("Ampere")^(2))=Z ("Henery")`