Some physical quanties are given in Column I and some possible SI units in which these quantities may be expressed are given in Column II. Match the physical quantities in Column I with the units in Column II.
`{:(,"Column I",,,"Column II"),((A),GM_(e)M_(s),,(p),("volt")("coulomb")("metre")),(,G-"universal gravitational constant",,,),(,M_(e)-"mass of the earth," M_(s)- "mass of the sun",,,),((B),(3RT)/(M),,(q),("kilogram")("metre")^(3)("second")^(-2)),(,R-"universal gas constant,",,,),(,T- "absolute temperature, M- molar mass",,,),((C),F^(2)/(q^(2)B^(2)),,(r),("metre")^(2)("second")^(-2)),(,F-"force,"q-"charge," B- "magnetic field",,,),((D),(GM_(e))/R_(e),,(s),("farad")("volt")^(2)(kg)^(-1)),(,G- "universal gravitational constant,",,,),(,M_(e)- "mass of the earth," R_(e)- "radius of the earth.",,,):}`

Answer

(A) PQ, (B) RS, (C) RS, (D) RS

Explanation

Match the column
(A) `F=(GM_(e)M_(s))/R^(2)`
`GM_(e)M_(s)=FxxL^(2)= "Work" xx "Metre"`
`= "Coulomb" xx "Volt" xx "Metre"`
`=ML^(2)T^(-2) xx "Metre"=(kg)("Metre")^(3)(S)^(-2)`
(B) `3/2 RT=` kinetic energy
`(3RT)/(M)=v^(2) rArr ("Metre")^(2)(S)^(-2)`
`1/2 QV=` Energy
`rArr (QV)/(M)=("Energy")/(m)=(("farad")("volt")^(2))/(kg)`
(C) `F^(2)/(q^(2)B^(2))=(q^(2) in^(2))/(q^(2)B^(2))rArr (in/B)^(2)=v^(2) rArr (r, s)`
(D) `(GMe)/R=("Work dome")/("Mass")rArr ("Velocity")^(2)rArr (r, s)`