Home
Class 11
PHYSICS
Using mass (M), length (L), time (T) and...

Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimension of permittivity is:

A

`ML^(-2)T^(2)A`

B

`M^(-1)L^(-3)T^(4)A^(2)`

C

`MLT^(-2)A`

D

`ML^(2)T^(-1)A^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`[in_(0)]=([Q^(2)])/([F][4pi][sigma^(2)])=(A^(2)T^(2))/(MLT^(-2)xxL^(2))=M^(-1)L^(-3)T^(4)A^(2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN|Exercise Exersice-03|7 Videos

  • MISCELLANEOUS

    ALLEN|Exercise ASSERTION-REASON|18 Videos

  • MISCELLANEOUS

    ALLEN|Exercise Part -II Example Some worked out Examples|1 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-IV|8 Videos

Similar Questions

Explore conceptually related problems

Taking velocity , time and force as the fundamental quantities , find the dimension of mass .

If force F, time T and length L are used as fundamental quantities then dimensional formula for density will be

Knowledge Check

  • Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimensions of permeability are :

    A
    `[M^(-1)LT^(-2)A]`
    B
    `[ML^(-2)T^(-2)A^(-1)]`
    C
    `[MLT^(-2)A^(-2)]`
    D
    `[MLT^(-1)A^(-1)]`

  • Using mass (M), "length"(L) , time (T) and current (A) as fundamental quantites the demension of permeability is

    A
    `[M^(-1)LT^(-2)A]`
    B
    `[ML^(-2)T^(-2)A^(-1)]`
    C
    `[MLT^(-2)A^(-2)]`
    D
    `[MLT^(-1)A^(-1)]`

  • Using mass (M) , length (L) , time (T) , and electric current (A) as fundamental quantities , the dimensions of permitivity will be

    A
    `[M LT^(-1) A^(-1)]`
    B
    `[M LT^(-2) A^(-1)]`
    C
    `[M^(-1) L^(-3) T^(4) A^(2)]`
    D
    `[M^(2) L^(-2)T^(-2) A]`

    • Similar Questions

    Explore conceptually related problems

    If velocity (V), time (T) and force (F) were chosen fundamental quantities, the dimensions of mass will be

    If mass (M), length (L) and force (F) are considered as fundamental quantities then, find the dimensional formula for time

    If force F, Length L and time T are chosen as fundamental quantities , the dimensioal formula for mass is

    If energy E, length L, and time T are taken as fundamental quantities .The dimensional formula of gravitational constant is

    If force F , Length L and time T are chosen as fundamental quantites, the dimensional formula for Mass is

    Home
    Profile