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Using mass (M), length (L), time (T) and...

Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimension of permittivity is:

A

`ML^(-2)T^(2)A`

B

`M^(-1)L^(-3)T^(4)A^(2)`

C

`MLT^(-2)A`

D

`ML^(2)T^(-1)A^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`[in_(0)]=([Q^(2)])/([F][4pi][sigma^(2)])=(A^(2)T^(2))/(MLT^(-2)xxL^(2))=M^(-1)L^(-3)T^(4)A^(2)`
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