The electric potential `V(z, y,z)` for a planar charge distribution is given by:
`V(x, y, z)={(0,,"for "x lt -d),(-V_(0)(1+x/d)^(2),,"for "-d le x le 0),(-V_(0)(1+2x/d),,"for "0 le x lt d),(-3V_(0),,"for " x gt d):}`
where `-V_(0)` is the potential at the origin and d is a distance. Graph of electric field as a function of position is given as

Options

A.
B.
C.
D.

Answer

A

Explanation

`E=(-dv)/(dx)`