At a distance of `5 cm and 10 cm` outward from the surface of a uniformly charged solid sphere, the potentials are `100 V and 75 V`, repectively. Then.

Options

A. potential at its surface is `150 V`
B. the charge on the sphere is `(5//3)xx10^(-10)C`
C. the electric field on the surface is `1500 V//m`
D. the electric potential at its centre is `225 V`

Answer

A, C, D

Explanation

Potential at 5 cm from surface`=(KQ)/(R+5)=100`
Potential at `10` cm from surface
`=(KQ)/(R+10)=75 rArr R=10` cm.
`:.` Potential at surface `=(KQ)/(R)=(100xx15)/10=150 V`
Electric field on surface`=(KQ)/R^(2)=(100xx15Vxxcm)/(100 cm^(2))`
`=1500 V//m`