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There are four concentric shells A,B, C and D of radii `a,2a,3a` and `4a` respectively. Shells B and D are given charges `+q` and `-q` respectively. Shell C is now earthed. The potential difference `V_A-V_C` is `k=(1/(4piepsilon_0))`

A

`(Kq)/(2a)`

B

`(Kq)/(3a)`

C

`(Kq)/(4a)`

D

`(Kq)/(6a)`

Text Solution

Verified by Experts

The correct Answer is:
D

Potential at `C=(Kq)/(3a)-(Kq)/(4a)+(Kq')/(3a)=0rArr q'=-q/4`
Potential at `A=(Kq)/(2a)-(Kq)/(4a)-(Kq/4)/(3a)=(Kq)/(6a)`
Hence `V_(A)-V_(C)=(Kq)/(6a)`
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